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Correctly handle json keymaps with ANY()

skullY 5 years ago
parent
commit
b4ef72423e
1 changed files with 13 additions and 1 deletions
  1. 13 1
      lib/python/qmk/keymap.py

+ 13 - 1
lib/python/qmk/keymap.py

@@ -11,7 +11,7 @@ DEFAULT_KEYMAP_C = """#include QMK_KEYBOARD_H
 
 /* THIS FILE WAS GENERATED!
  *
- * This file was generated by qmk-compile-json. You may or may not want to
+ * This file was generated by qmk json2c. You may or may not want to
  * edit it directly.
  */
 
@@ -39,6 +39,15 @@ def template(keyboard):
     return DEFAULT_KEYMAP_C
 
 
+def _strip_any(keycode):
+    """Remove ANY() from a keycode.
+    """
+    if keycode.startswith('ANY(') and keycode.endswith(')'):
+        keycode = keycode[4:-1]
+
+    return keycode
+
+
 def generate(keyboard, layout, layers):
     """Returns a keymap.c for the specified keyboard, layout, and layers.
 
@@ -53,9 +62,12 @@ def generate(keyboard, layout, layers):
             An array of arrays describing the keymap. Each item in the inner array should be a string that is a valid QMK keycode.
     """
     layer_txt = []
+
     for layer_num, layer in enumerate(layers):
         if layer_num != 0:
             layer_txt[-1] = layer_txt[-1] + ','
+
+        layer = map(_strip_any, layer)
         layer_keys = ', '.join(layer)
         layer_txt.append('\t[%s] = %s(%s)' % (layer_num, layout, layer_keys))